Two cyclists leave towns apart at the same time and travel toward each other. One cyclist travels slower than the other. If they meet in hours, what is the rate of each cyclist?
Do you see what's missing?
To find the rates of the two cyclists, we can use the formula:
Rate = Distance / Time
Let's assume that the faster cyclist's rate is R1 (in units per hour) and the slower cyclist's rate is R2 (in units per hour).
Since they are traveling towards each other, their distances traveled will add up to the total distance between the two towns.
Let's say the total distance between the two towns is D (in units).
Now, we know that the time taken by both cyclists to meet is given as 2 hours.
Using the formula:
Distance = Rate * Time
The distance traveled by the faster cyclist (R1) in 2 hours is 2 * R1.
Similarly, the distance traveled by the slower cyclist (R2) in 2 hours is 2 * R2.
Since the distances traveled by both cyclists add up to the total distance, we have:
2 * R1 + 2 * R2 = D
Now, we can solve this equation to find the rates of the two cyclists. However, we need one more equation to solve for the unknowns R1 and R2.
Do you have any additional information, such as the total distance between the two towns, or any other relationships between the rates of the two cyclists?