Calculates the work done (in joules) when 42.8 g of tin dissolves in excess acid at 1.10 atm and 23 degrees Celcius. Assume ideal gas behaviour.

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  1. Try this.
    Sn + 2HCl ==> SnCl2 + H2
    mols Sn = 42.8/atomic mass Sn
    mols H2 = mols Sn
    Then PV = nRT
    You know n, R, T, solve for PV and that is work of expansion of the gas. The unit is L*atm. Multiply by 101.325 to convert to joules.

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