How many milligram of lysozyme (MW=14,600 g/mol) are needed to make 3 liters of a 10^-6 M solution?
To find out how many milligrams of lysozyme are needed to make a 10^-6 M solution in 3 liters, we need to use the formula:
Mass (in grams) = Molarity (in moles/L) × Molecular weight (in g/mol) × Volume (in L)
First, let's convert the molarity to moles per liter (mol/L). The given molarity is 10^-6 M, which means there is 10^-6 moles of lysozyme in every 1 liter of solution.
Next, we multiply the molarity in moles per liter by the volume of the solution. The volume given is 3 liters.
So, the number of moles of lysozyme in the solution is:
Moles = Molarity × Volume
= 10^-6 mol/L × 3 L
= 3 × 10^-6 moles
Finally, we can calculate the mass of lysozyme in grams using the molecular weight (MW) given:
Mass (in grams) = Moles × Molecular weight
= 3 × 10^-6 moles × 14,600 g/mol
= 43.8 × 10^-6 grams
= 43.8 milligrams
Therefore, you would need 43.8 milligrams of lysozyme to make a 10^-6 M solution in 3 liters.