Find the equation of the circle having the given center and radius.
center (-5,1), radius 6 squared.
surely your text says that the circle with center at (h,k) and radius r is
(x-h)^2 + (y-k)^2 = r^2
Just plug in your given values.
To find the equation of a circle, we use the standard form equation, which is:
(x - h)^2 + (y - k)^2 = r^2
where (h, k) represents the center of the circle, and r represents the radius.
In this case, the given center is (-5, 1), and the given radius squared is 6^2 = 36.
Substituting the values into the equation, we have:
(x - (-5))^2 + (y - 1)^2 = 36
Simplifying further, we get:
(x + 5)^2 + (y - 1)^2 = 36
So, the equation of the circle with center (-5, 1) and radius 6 squared is (x + 5)^2 + (y - 1)^2 = 36.