chemistry

For the reactions that occurred spontaneously in the individual tables, balance these reactions assuming they are in an acidic solution.

Reaction 1:
Cu
I^-
Ag
Br^-

Reaction 2:
Zn
Pb
Cu
Ag

Reaction 3:
Cl2
Br2
I2

Reaction 1
I 2(aq) Cu2 + (aq) Ag + (aq) Br2 (aq)

Reaction 2
Ag + (aq) Pb2 + (aq) Cu2 + (aq) Zn2 +(aq)

Reaction 3
Br - (aq) Cl - (aq) I - (aq)

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asked by Joseph
  1. Your notation is still somewhat confusing to me but here is what you do for one of the reactions. The others are done the same way.
    For the copper, Ag^+ reaction:
    Cu ==> Cu^+2 + 2e
    Ag^+ + e ==> Ag
    ====================
    The electrons must be kept equal; therefore, multiply the first equation by 1 and the second equation by 2, then add them.
    Cu + 2Ag^+ ==> Cu^+2 + 2Ag.

    The others are done the same way.

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