got a couple of calculus questions
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find the equation of a quadratic function whose graph is tangent at x=1 to the line whose slope8, tangent at x=2 to solve the line with slope4 and tangent to the line y=8 find the equation of the tangent lines at x=1 and x=2
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find the equation of a quadratic function whose graph is tangent at x=1 to the line whose slope8, tangent at x=2 to solve the line with slope4 and tangent to the line y=8
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asked by Ray on November 19, 2016 
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Suppose f(x) is differentiable at x=a. What does tangent line approximation, y=, mean? Select all that apply (A) Local linearization (B) y=f(x)f(a)f'(a)(xa) (C) The best liner approximation of f(x) near a (D) After zooming y is
asked by George on November 5, 2008 
Calculus
Suppose f(x) is differentiable at x=a. What does tangent line approximation, y=, mean? Select all that apply (A) Local linearization (B) y=f(x)f(a)f'(a)(xa) (C) The best liner approximation of f(x) near a (D) After zooming y is
asked by George on November 5, 2008 
Calculus
Suppose f(x) is differentiable at x=a. What does tangent line approximation, y=, mean? Select all that apply (A) Local linearization (B) y=f(x)f(a)f'(a)(xa) (C) The best liner approximation of f(x) near a (D) After zooming y is
asked by George on November 5, 2008 
Calculus
Suppose f(x) is differentiable at x=a. What does tangent line approximation, y=, mean? Select all that apply (A) Local linearization (B) y=f(x)f(a)f'(a)(xa) (C) The best liner approximation of f(x) near a (D) After zooming y is
asked by George on November 5, 2008 
Calculus
If F(x)=x^3−7x+5, use the limit definition of the derivative to find FŒ(5), then find an equation of the tangent line to the curve y=x^3−7x+5 at the point (5, 95). FŒ(5)= The equation of the tangent line is y = x + .
asked by Rachael on June 9, 2013 
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Could someone please help me with these tangent line problems? 1) Find the equation of the line tangent to the given curve at the indicated point: 3y^3 + 2x^2 = 5 at a point in the first quadrant where y=1. 2) Show that there is
asked by Annie on November 25, 2016