math

The launch site for trigon balloon co. is 250 ft above sea level. A hot air balloon is launched from the site and begins to rise at a rate of 110 ft/min. At the same time, another balloon 2200 ft above sea level begins to descend at a rate of 150 ft/min.

A. How long will it be unit the balloons are at the same elevation?

B. What will their elevation be then?

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  1. balloon#1 = 250 + 110t
    balloon#2 = 2200 - 150t

    When they reach the same height,
    250 + 110t = 2200 - 150t
    260t = 1950
    t = 7.5 ----- 7 min, 30 seconds

    how high? plug t = 7.5 into either equation, you must get the same result for each case

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  2. I don't under stand how to do 1/3 + 1/10 = what!

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