Use d=1/2gt2 and solve for the time one spends moving upward in a 0.6-m vertical jump. Then double it for the "hang time"-the time one's feet are off the ground.
To solve for the time spent moving upward in a vertical jump using the formula d = 1/2gt^2, where d represents the vertical distance traveled, g is the acceleration due to gravity, and t is the time taken:
1. Identify the given values:
- Vertical distance, d = 0.6 m
- Acceleration due to gravity, g = 9.8 m/s^2 (approximate value)
2. Rearrange the formula to isolate time (t):
d = 1/2gt^2
0.6 = 1/2 * 9.8 * t^2
0.6 = 4.9t^2
3. Divide both sides of the equation by 4.9 to isolate t^2:
(0.6 / 4.9) = (4.9t^2 / 4.9)
0.12245 = t^2
4. Take the square root of both sides to solve for t:
t = √0.12245
t ≈ 0.35 s (rounded to two decimal places)
Therefore, the time spent moving upward in a 0.6 m vertical jump is approximately 0.35 seconds.
To find the "hang time," which is the time both feet are off the ground, you need to double the time spent moving upward. Hence, the hang time would be approximately 0.35 seconds * 2 = 0.70 seconds.