How many milliliters of 1.5 M HCl must be transferred from a reagent bottle to provide 25g HCl for a reaction?
25g HCl = ? mols
25/36.5 = about 0.685 mols HCl.
mols HCl = M x L
0.685 = 1.5M x L
Solve for L and convert to mL.
To find the number of milliliters of 1.5 M HCl required, we can use the relationship between the amount of solute (moles) and the concentration (molarity) of the solution. The formula that establishes this relationship is:
moles = concentration × volume
First, we need to determine the number of moles required. This can be found using the molar mass of HCl, which is approximately 36.46 g/mol.
moles = mass / molar mass
moles = 25 g / 36.46 g/mol
moles ≈ 0.686 mol
Now, we can rearrange the formula to solve for volume:
volume = moles / concentration
volume = 0.686 mol / 1.5 mol/L
volume ≈ 0.457 L
Since the concentration is given in molarity, and 1 L = 1000 mL, we can convert liters to milliliters by multiplying by 1000:
volume = 0.457 L × 1000 mL/L
volume ≈ 457 mL
Therefore, approximately 457 milliliters of 1.5 M HCl must be transferred from the reagent bottle to provide 25 grams of HCl for the reaction.