Algebra  Equations
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AlgebraPlease check my answers
Posted by Jessie on Monday, October 18, 2010 at 3:48pm. I think I figured it outplease check I'm really stuck on these problems Simplify 6xy(3xy)^2? I think this is 2/3xy choices were 2/xy 3xy 2xy 2/3xy Simplify 12xyz^2/8x^2z
asked by Jessie on October 18, 2010 
AlgebraPlease check my answers
Posted by Jessie on Monday, October 18, 2010 at 3:48pm. I think I figured it outplease check I'm really stuck on these problems Simplify 6xy(3xy)^2? I think this is 2/3xy choices were 2/xy 3xy 2xy 2/3xy Simplify 12xyz^2/8x^2z
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X+y+z=1......(1) x^2+y^2+z^2=35........(2) x^3+y^3+z^3=97.........(3) solution but from 3 (x^3+y^3)=(x+y)^33xy(x+y)......(4) puting 4 into 3 bck (x+y)^33xy(x+y)+z^3=97.......(5) now from 1 x+y=1z......(6) putin 6 into 7 we have
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Find the derivative of sin(2x + 3y)= 3xy + 5y2. I have this so far 1) cos(2x+3y) * d/dx (2x+3y)= 3xy' + 3y + 5y' 2) cos (2x+3y) * [2 + 3y']= 3xy' + 3y + 5y' 3) 3y' cos (2x+3y) + 2cos(2x+3y)= 3xy' + 3y + 5y' 4) 3xy' + 5y' 
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asked by Anonymous on September 14, 2014 
bobpursly,
Is this correct now after i revised it Multiply. 3xy^2(5xy4x+6y) 3xy^2(5xy)=15x^2y^3 3xy^2(4x)=12x^2y^2 3xy^2(6y)=18xy^3 so i get from this 15x^2y^312x^2y^2+18xy^3 correct awsome i just thought that the 15x^2y^312x^2y^2
asked by jas20 on February 28, 2007