# Algebra 2

Express as a single logarithm.

1/2 log base b of (x-2)- log base b of y + (3 log base b of z) = log base 6 of (x-2)^1/2

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1. (1/2) logb(x-2) - logby + 3logbz = log6(x-2)^(1/2)

logb [ (x-2)^(1/2) z/y] = log6(x-2)^(1/2)

logb ( (z/y)√(x-2) ) = log6 √(x-2)

are you sure the right side was not supposed to be
logb ?

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posted by Reiny
2. oops, didn't notice the 3 coefficient until I checked the display of this post.

should have been: z^3 in the last two lines.

logb (x^3/y)logb(x-2) = log6 √(x-2)

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posted by Reiny

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