# phsics

a car moving with an initial velocity of 60 m/s south has a constant acceleration of 10 m/s^2 north. After 12 seconds its velocity will be:
A) 60 m/s south B)60 m/s north C) 40 m/s north D) 40 m/s south

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1. Use the following formula and solve for Vf

Vf=Vi+at

Where

Vf=?
Vi=60m/s
a=-10m/s^2
t=12s

**Since the acceleration is in the opposite direction of the velocity, acceleration is negative.

Vf=60m/s+[(-10m/s^2)(12s)]
Vf=-60m/s

Velocity is in the opposite direction, then velocity initial, so -60m/s is 60m/s north

B is the best answer choice.

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posted by Devron

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