I need to find x of the quadratic function y=-3/4x^2-4x-1 and keep getting (4)/(3/2). Is this right and if so, can it be reduced?
-or+2((sqrt13-3y)+4) divided by 3
Just FYI, if you come up with what you feel is a wrong answer (or even a correct one, if you want verification), it's best to post your work, so we can see where you went astray.
To find the x-intercepts of a quadratic equation, you need to solve the equation for x when y is equal to 0. In this case, the equation is y = -3/4x^2 - 4x - 1.
Setting y equal to 0, we have:
0 = -3/4x^2 - 4x - 1
To solve this equation, you can use the quadratic formula, which states that for any quadratic equation ax^2 + bx + c = 0, the solutions for x can be found using the formula: x = (-b ± √(b^2 - 4ac)) / 2a.
Comparing this with our equation, we have a = -3/4, b = -4, and c = -1.
Plugging these values into the quadratic formula, we get:
x = (-(-4) ± √((-4)^2 - 4(-3/4)(-1))) / (2 * (-3/4))
Simplifying further, we have:
x = (4 ± √(16 + 3)) / (-3/2)
x = (4 ± √19) / (-3/2)
x = (4 ± √19) / (-3/2) * (2/2)
x = (4 ± √19) / (-3)
So, the solution for x is:
x = (4 ± √19) / (-3)
It seems that you obtained the correct solution, (4 ± √19) / (-3). This cannot be further reduced, as it is already in its simplest form.