calculus help work

a force of 1250 pounds compresses a spring 5 inches from its natural length. find the work done in compressing the spring 8 additional inches.

f=kd
1250=k5
k=250

then what do i do. i have to do this the calculus way, not the physics way. by using integrals

the answer choices are:
a.3250
b.21,125
c.18000
d.2000
e. none of these

are you in grade 12? do you wear ties and hats? is your middle name caleb? (im serious! i think i know you!)

and i am not sure about the question... sorry!

  1. 👍 0
  2. 👎 0
  3. 👁 129
asked by david

Respond to this Question

First Name

Your Response

Similar Questions

  1. calculus help plz

    a force of 1250 pounds compresses a spring 5 inches from its natural length. find the work done in compressing the spring 8 additional inches. f=kd 1250=k5 k=250 then what do i do. the answer choices are: a.3250 b.21,125 c.18000

    asked by david on January 8, 2007
  2. Math

    Hooke's Law states that the distance a spring will stretch beyond its natural length varies directly with the force applied to the spring. A force of 12 pounds is needed to stretch a certain spring 9 inches beyond its natural

    asked by Sami on January 27, 2016
  3. Pre-calculus

    Hooke's Law states that the distance a spring will stretch beyond its natural length varies directly with the force applied to the spring. A force of 12 pounds is needed to stretch a certain spring 9 inches beyond its natural

    asked by Sami on January 28, 2016
  4. calculus/physics

    A force of 10 pounds stretches a spring 2 inches. Find the work done in stretching this spring 3 inches beyond its natural length

    asked by deb on March 11, 2010
  5. work force

    a force of 10 pounds is required to stretch a spring of 4 inches beyond it's natural length. assuming hooke's law applies, how much work is done in stretching the spring from its natural length to 6 inches beyond its natural

    asked by david on April 13, 2007
  6. Calculus/Physics

    A spring has a natural length of 10in. An 800lb force stretches the spring to 14in. A. Find the force constant B. How much work is done in stretching the spring from 10 to 12 inches? C. How far beyond its natural length will a

    asked by Tim on May 2, 2014
  7. Pre-Calculus

    The amount of force required to compress a spring is inversely proportional to the distance that it has been compressed. For one certain spring, it takes 5 pounds of force to compress it from its natural length of 18 inches down

    asked by Karen on November 14, 2016
  8. Math-Hooke's law

    Using Hooke's Law (F=kx) determine: A) A weight of 5 pounds stretches a certain spring from its natural length of 10.2 inches to a length of 10.5 inches. Find K. B) What weight will stretch the spring in part (A) to a length of

    asked by Leah on July 16, 2013
  9. Calculus

    A force of 6 pounds is required to hold a spring stretched 0.2 feet beyond its natural length. How much work (in foot-pounds) is done in stretching the spring from its natural length to 0.6 feet beyond its natural length? could

    asked by john on October 26, 2015
  10. Integral Calculus

    A force of 4 pounds is required to hold a spring stretched 0.1 feet beyond its natural length. How much work (in foot-pounds) is done in stretching the spring from its natural length to 0.6 feet beyond its natural length?

    asked by Mackenzie on October 15, 2014

More Similar Questions