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calculus help plz
a force of 1250 pounds compresses a spring 5 inches from its natural length. find the work done in compressing the spring 8 additional inches. f=kd 1250=k5 k=250 then what do i do. the answer choices are: a.3250 b.21,125 c.18000
asked by david on January 8, 2007 
Math
Hooke's Law states that the distance a spring will stretch beyond its natural length varies directly with the force applied to the spring. A force of 12 pounds is needed to stretch a certain spring 9 inches beyond its natural
asked by Sami on January 27, 2016 
Precalculus
Hooke's Law states that the distance a spring will stretch beyond its natural length varies directly with the force applied to the spring. A force of 12 pounds is needed to stretch a certain spring 9 inches beyond its natural
asked by Sami on January 28, 2016 
calculus/physics
A force of 10 pounds stretches a spring 2 inches. Find the work done in stretching this spring 3 inches beyond its natural length
asked by deb on March 11, 2010 
work force
a force of 10 pounds is required to stretch a spring of 4 inches beyond it's natural length. assuming hooke's law applies, how much work is done in stretching the spring from its natural length to 6 inches beyond its natural
asked by david on April 13, 2007 
Calculus/Physics
A spring has a natural length of 10in. An 800lb force stretches the spring to 14in. A. Find the force constant B. How much work is done in stretching the spring from 10 to 12 inches? C. How far beyond its natural length will a
asked by Tim on May 2, 2014 
PreCalculus
The amount of force required to compress a spring is inversely proportional to the distance that it has been compressed. For one certain spring, it takes 5 pounds of force to compress it from its natural length of 18 inches down
asked by Karen on November 14, 2016 
MathHooke's law
Using Hooke's Law (F=kx) determine: A) A weight of 5 pounds stretches a certain spring from its natural length of 10.2 inches to a length of 10.5 inches. Find K. B) What weight will stretch the spring in part (A) to a length of
asked by Leah on July 16, 2013 
Calculus
A force of 6 pounds is required to hold a spring stretched 0.2 feet beyond its natural length. How much work (in footpounds) is done in stretching the spring from its natural length to 0.6 feet beyond its natural length? could
asked by john on October 26, 2015 
Integral Calculus
A force of 4 pounds is required to hold a spring stretched 0.1 feet beyond its natural length. How much work (in footpounds) is done in stretching the spring from its natural length to 0.6 feet beyond its natural length?
asked by Mackenzie on October 15, 2014