What is the force on the charge located at x = +8.00 cm. q = 1.00 µC and a = 8.00? (The positive direction is to the right.)
To find the force on a charge located at a given position, we can use Coulomb's Law. Coulomb's Law states that the magnitude of the force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. The formula for Coulomb's Law is:
F = k * (q1 * q2) / r^2
Where:
F is the magnitude of the force between the charges,
k is Coulomb's constant (approximately 9.0 x 10^9 N m^2 / C^2),
q1 and q2 are the charges of the two objects, and
r is the distance between the charges.
In this case, we have a single charge (q = 1.00 µC) located at x = +8.00 cm. We need to calculate the force on this charge.
First, we need to convert the charge from microcoulombs (µC) to coulombs (C):
q = 1.00 µC = 1.00 x 10^-6 C
Next, we calculate the distance (r) using the given position:
r = 8.00 cm = 8.00 x 10^-2 m
Now, we can substitute the values into Coulomb's Law to calculate the force:
F = (9.0 x 10^9 N m^2 / C^2) * [(1.00 x 10^-6 C) * (1.00 x 10^-6 C)] / [(8.00 x 10^-2 m)^2]
Calculating this expression will give us the force on the charge located at x = +8.00 cm.