calculus

The volume of a solid is given by V=pi x^2(lnx)^2. what is the approximate change in the volume when x is increased from 2.718 to 3.000?

dv= PI 2x(lnx)^2 dx + Pix^2 *2lnx * 1/x reduce that.

For x, use 2.718

dx= 3-2.718

check my thinking.

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asked by Mischa
  1. Yes, that is correct. After that, plug in the numbers and you get an answer of dV=9.630.

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    posted by Julia

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