Solution A is 25% acid and Solution B is 40% acid. How much of each is needed to make 60 liters of a solution that is 30% acid?
To find out how much of each solution is needed, we can set up a system of equations:
Let's say x liters of Solution A is needed.
Therefore, (60 - x) liters of Solution B is needed.
The equation representing the amount of acid in Solution A is: 0.25x
The equation representing the amount of acid in Solution B is: 0.4(60 - x)
Since we want to make a 60-liter solution that is 30% acid, we can set up the equation:
0.3(60) = 0.25x + 0.4(60 - x)
Simplifying the equation gives us:
18 = 0.25x + 24 - 0.4x
Combining like terms:
0.15x = 6
Now, solve for x:
x = 6 / 0.15
x = 40
Therefore, 40 liters of Solution A (25% acid) and (60 - 40) = 20 liters of Solution B (40% acid) are needed to make a 60-liter solution that is 30% acid.