If 25 grams of solid ice at-20 degrees C is heated to gaseous water at 125 degrees C, how much energy is required?

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asked by joe
  1. q1 = heat to warm ice from -20 to zero but not melt it.
    q1 = mass ice x specific heat ice x delta T (delta T = 20).

    q2 = heat to melt ice at zero.
    q2 = mass ice x heat fusion.

    q3 = heat to raise temperature from zero for liquid water to 100 C.
    q3 = mass water x specific heat water x delta T (100 is delta T).

    q4 = heat to change water from liquid to steam at 100.
    q4 = mass water x heat vaporization.

    q5 = heat to raise steam from 100 to 125 C.
    q5 = mass steam x specific heat steam x delta T.

    Total energy is q1 + q2 + q3 + q4 + q5.
    You will need to look up specific heat ice, specific heat water, specific heat steam, heat of fusion and heat of vaporization.
    Post your work if you get stuck.

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