chem

20ml sample of .200M HBr is titrated w/ .200M NaOH. what is the ph after adding 15ml (base)?

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  1. HBr + NaOH ==> NaBr + HOH

    Calculate mols HBr.
    mols HBr = M x L = ??
    Calculate mols NaOH used = M x L.

    Subtract mols of one from mol of the other. The one in excess will give you the H^+ if it is HBr or OH^- if it is NaOH.
    Then pH = -log(H^+) OR
    pOH = -log(OH^-)

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