Circuit Problem- Physics

I am trying to do these 2 problems. I'm starting out with the RC Circuit (2nd one):
h t t p ://img201.imageshack.us/my.php?image=circuit5ij7.png
*delete spaces or link won't load!

a) The capacitor acts as a bare wire with no resistance, so:
I=V/R=V/(4/5R)
b) Capacitor acts as an open circuit, so:
I=V/R=V/(4R)

Are those right so far?

I need a little help on c, d, and e.

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asked by Eileen
  1. What were the questions? What is the circuit?

    A capacitor acts as an open circuit to DC, but has no resistance.

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    posted by drwls
  2. The questions is in the link I gave above. Here it is again (you have to delete the spaces in 'h t t p :'):

    h t t p ://img201.imageshack.us/my.php?image=circuit5ij7.png

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    posted by Eileen
  3. Sorry, I forgot to check out the link with the circuit and the questions. That was clever of you to add the spaces in h t t p so the URL could be displayed.

    (a) Initially, C looks like zero resistance, so the effective resistance seen but the battery is 4R/5

    (b) steady state I = V/R, since the capacitor cannot allow DC current

    (c) current = 0 through the battery, but V/(5R) through 4R, and the capacitor discharges.
    (d) Solve exp[-t/(5RC)] = 0.5 , for t.
    5RC is the series resistance that the capacitor sees while discharging
    (e) (1/2) C V^2 is the energy dissipated in resistors while discharging

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    posted by drwls

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