Chemistry

how do i write the complete electron configuration for Ga3+ and Mg2+????????????

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  1. Ga3+
    The atomic number of neutral Ga is 31. Atomic number is equal to the number of electrons if the atom is neutral. Since it has a charge of 3+, it means it lost 3 electrons. Therefore, 31 - 3 = 28. Writing the e config: (recall aufbau principle)
    Ga : 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p1
    Ga 3+ : 1s2 2s2 2p6 3s2 3p6 4s0 3d10
    or in Noble Gas core notation,
    Ga3+ : [Ar]4s0 3d10

    Note that 4s electrons are lost before 3d electrons thus, the electrons are deducted first to the 4s rather than 3d.

    Mg2+
    Atomic number of Mg is 12. Since the charge is 2+, 2 electrons are lost. Thus, 12 - 2 = 10:
    Mg : 1s2 2s2 2p6 3s2
    Mg2+ : 1s2 2s2 2p6

    Hope this helps~ :)

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