A gardener pulls a roller along the ground through a distance of 20 m.if he applies a force of 20 kg wt in a direction inclined at 60 degree to the ground.find the work done by him (take g=10m\s )
20 kg wt = 200 Newtons
Force Component along ground
= 200*cos 60 = 100 N
Work = 20 * 100 = 2000 J
20kgwt=200N, w=fscos60,, W=200*20*1/2. . w=2000j
To find the work done by the gardener, we can use the formula:
Work = Force × Distance × cos(theta)
Where:
- Force is the applied force in Newtons
- Distance is the distance over which the force is applied in meters
- theta is the angle between the force and the direction of motion
Note: 1 kg wt is equal to the weight of 1 kg and acceleration due to gravity (g = 10 m/s^2).
In this case, the gardener applies a force of 20 kg wt (200 N) at an angle of 60 degrees to the ground and pulls the roller over a distance of 20 m.
So, let's calculate the work:
Work = 200 N × 20 m × cos(60 degrees)
= 200 N × 20 m × 0.5
= 2000 J
Therefore, the gardener does 2000 Joules of work by pulling the roller through a distance of 20 m.
W=Fscos$ where $ is angle
W=20×10×20×1/2=2000J
20 kg wt = 200 Newtons
Force Component along ground
= 200*cos 60 = 100 N
Work = 20 * 100 = 200 J