Volume of distilled water used 12.09 mL
Volume of HCl added 0.87 mL
Concentration of added HCl 1.979 M
pH of diluted HCl solution ___________________
HCl is a strong acid, so the pH=-log[Molarity of HCl]
Calculate the molarity of HCl
Molarity of HCl=[(0.87mL)*(1.979)]/12.96mL]
Plug in the numbers and solve.
To determine the pH of a diluted HCl solution, we need to consider the dilution factor and the initial concentration of the HCl before dilution.
The dilution factor can be calculated using the formula:
Dilution Factor (DF) = Final Volume (Vf) / Initial Volume (Vi)
In this case, the initial volume of HCl added was 0.87 mL, and the volume of distilled water used was 12.09 mL. Therefore, the final volume of the solution after dilution is:
Vf = Vi + Volume of distilled water used
= 0.87 mL + 12.09 mL
= 12.96 mL
Now, let's calculate the dilution factor:
DF = Vf / Vi
= 12.96 mL / 0.87 mL
≈ 14.92
The concentration of the added HCl is given as 1.979 M.
Next, we can calculate the new concentration of the diluted HCl solution using the formula:
New Concentration (Cf) = Concentration of added HCl (Ci) / Dilution Factor (DF)
Cf = 1.979 M / 14.92
≈ 0.132 M
Now, to determine the pH of the diluted HCl solution, we can use the pH scale equation:
pH = -log[H+]
Since HCl is a strong acid that fully ionizes in water, the concentration of H+ ions will be equal to the concentration of the diluted HCl solution.
pH = -log(0.132)
≈ 0.88
Therefore, the pH of the diluted HCl solution is approximately 0.88.