Volume of distilled water used 12.09 mL
Volume of HCl added 0.87 mL
Concentration of added HCl 1.979 M

pH of diluted HCl solution ___________________

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  1. HCl is a strong acid, so the pH=-log[Molarity of HCl]

    Calculate the molarity of HCl

    Molarity of HCl=[(0.87mL)*(1.979)]/12.96mL]

    Plug in the numbers and solve.

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