Q2_1_2 Answers
1) (TCX+2Lt0)/(G0I) where TCx=-t0L/3
2) t0(3L-x))/(2G0I)
3) x=3L
Q2_1_1 Answer
TCx=-t0L/3
I need to know if this information is correct, because I solved the problems without correspondent images
Let me know if solutions are correct to go with the next problems.
I put this Q2_1_1 Answer but the answer its wrong i put this -t_0*(L/3) and the answer is wrong
Q2_1_2 Answers
1) (TCX+2Lt0)/(G_0I) where TCx=-t_0L/3
and I=pi*R^4/2 so answer:
(2*TCX+4*L*t_0)/(G_0*pi*R^4)
2) t0(3L-x))/(2G0I)
where I=i*R^4/2 so
answer: ((t_0*(3L-x))/(pi*R^4)
3) x=3L
Where I can see images of the problems ?
here
imagehousing. com /imageupload.php?id=1149147
ww.imagehousing. com/imageupload.php?id=1149147
OK Let me see Answer Q2_1_1:
Sum=0
-Tx_1+INTEGRAL{3L-L}t_0*dx+TXC=0
so Tx_1=2*L*t_0+TXC {0<=x<=L}
-Tx_2+INTEFRAL{3L-x}t_0*dx+TXC=0
so Tx_2=t_0*(3L-x)+TXC {L<=x<=3L}
d*phi/dx =Tx/GI
so in x<=_x<=L
d*phi/dx= (TXC+2*L*t_0)/G_0*I
in L<=x<=3L
d*phi/dx= (t_0*(3L-x)+TXC)/(2G_0*I)
in x=3l Phi=0
so
0=INTEGRAL{0,L}(TXC+2*L*t_0)/G_0*I+INTEGRAL{L,3L}(t_0*(3L-x)+TXC)/(2G_0*I)
0=(3*L*TXC+3*L^2*t_0)/(g_0*I)
TXC=-L*t_0
Ok, I believe that this is the correct answer for Q2_1_1
Solving for TXC
TXC=
Is it correct ? If yes I will going with the second
I'm waiting your answers, to follow with next items.
TXC=-L*t_0, its wrong!
if can you help!!
tnks!
TXC=-3/2*t_0*L
Q2_1_2:
d*phi/dx = (t_0*L)/(pi*G_0*R^4)
d*phi/dx = (t_0*(3*L-2*x))/(2*pi*G_0*R^4)
x0 = 3/2*L
some one for the rest?
Q2_1_3:
rômax = R
xômax =3*L
access is your answers are ok, then
Q2_1_3
a) shear stress mx=(4*t_0*L)/(pi*R^3)
Is it ok?
Q2_1_1
TXC=-3/2*t_0*L
Q2_1_2:
d*phi/dx = (t_0*L)/(pi*G_0*R^4)
d*phi/dx =t_0*(3*L-2*x))/(2*pi*G_0*R^4)
x0 = 3/2*L
Q2_1_3:
tau max=(4*t_0*L)/(pi*R^3)
r tau max = R
x tau max =3*L
•MITx: 2.01x - ElementarySchoolStudent, Saturday, July 27, 2013 at 2:12am
Q2_1_1
TXC=-3/2*t_0*L
Q2_1_2:
d*phi/dx = (t_0*L)/(pi*G_0*R^4)
d*phi/dx =t_0*(3*L-2*x))/(2*pi*G_0*R^4)
x0 = 3/2*L
Q2_1_3:
tau max=(4*t_0*L)/(pi*R^3)
r tau max = R
x tau max =3*L
Q2_1_4
1) phi=(9*t_0*L^2)/(2*pi*G_0*R^4)
2) x phi max=3*L/2
I have only one more chance, please help me and tell me if this answers I put here are ok.
Q2_1_4
A little error when I got out a factor of 2, I put it in the numerator and must be in the denominator so the correct answer is.
1) phi=(9*t_0*L^2)/(8*pi*G_0*R^4)
Q2_1_3:
This is the correct answer 3 instead of 4. I added wrong.
1) tau max=(3*t_0*L)/(pi*R^3)