
 👍 0
 👎 0
posted by drwls
Respond to this Question
Similar Questions

PreCalc
Trigonometric Identities Prove: (tanx + secx 1)/(tanx  secx + 1)= tanx + secx My work so far: (sinx/cosx + 1/cosx + cosx/cosx)/(sinx/cos x  1/cosx + cosx/cosx)= tanx + cosx (just working on the left side) ((sinx + 1 
asked by Dave on January 2, 2007 
Precalculus/Trig
I can't seem to prove these trig identities and would really appreciate help: 1. cosx + 1/sin^3x = cscx/1  cosx I changed the 1: cosx/sin^3x + sin^3x/sin^3x = cscx/1cosx Simplified: cosx + sin^3x/sin^3x = cscx/1cosx I don't
asked by Heather on August 15, 2014 
PreCalculus
How do you verify: 1.) sinxcosx+sinx^3secx=tanx 2.) (secx+tanx)/(secxtan)=(secx+tanx)^2 I tried starting from the left on both problems, but am stuck. like I said before, change everything into sines and cosines. for the first
asked by Corin on May 4, 2007 
Simplifying with Trigonometry Identities
Hi, I am a senior in High School having a really difficult time with two problems. I have to prove using the trigonometric identities that they equal each other but I am having a really hard time trying to get them to equal each
asked by amanda on March 7, 2007 
Trigonometry
Prove the following trigonometric identities. please give a detailed answer because I don't understand this at all. a. sin(x)tan(x)=cos(x)/cot^2 (x) b. (1+tanx)^2=sec^2 (x)+2tan(x) c. 1/sin(x) + 1/cos(x) = (cosx+sinx)(secx)(cscx)
asked by Jessy on November 24, 2013 
Calculus 2 Trigonometric Substitution
I'm working this problem: ∫ [1tan^2 (x)] / [sec^2 (x)] dx ∫(1/secx)[(sin^2x/cos^2x)/(1/cosx) ∫cosxsinx(sinx/cosx) ∫cosx∫sin^2(x)/cosx sinx∫(1cos^2(x))/cosx sinx∫(1/cosx)cosx sinx∫secx∫cosx
asked by Janice on March 15, 2015 
precal
1/tanxsecx+ 1/tanx+secx=2tanx so this is what I did: =tanx+secx+tanxsecx =(sinx/cosx)+ (1/cosx)+(sinx/cosx)(1/cosx) =sinx/cosx+ sinx /cosx= 2tanxI but I know this can't be correct because what I did doesn't end as a
asked by olivia on March 25, 2012 
PreCalculus
How can this identity be proved/verified? cscxsinx=1/(secxtanx) I have tried starting on both sides of the equation to get to the other. By starting on one side of the equation and manipulating it to make it look like the other
asked by Corin on May 3, 2007 
drwls
My previous question: Verify that (secx/sinx)*(cotx/cscx)=cscx is an identity. (secx/sinx)*(cotx/cscx) = (secx/cscx)(cotx/sinx) = (sinx/cosx)*cotx*(1/sinx) "The last steps should be obvious" Not to me. I can convert (sinx/cosx) to
asked by Jon on March 7, 2008 
Calculus
Q: If y=sinx/(1+tanx), find value of x not greater than pi, corresponding to maxima or minima value of y. I have proceeded thus Equating dy/dx=0 we get{ (1+tanx)cosxsinx.sec^2 x}/(1+tanx)^2=0……..(A) Or cosx+sinx=sinx.sec^2 x
asked by MS on June 16, 2014