When 85.0 g of CH4 are mixed with 160. g of O2 the limiting reactant is __________.
CH4 + 2O2 �¨ CO2 + 2H2O
A) CH4
B) O2
C) CO2
D) H2O

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  3. 👁 5,015
  1. CH4 + O2 ==> CO2 + 2H2O
    mols CH4 = grams/molar mass = ?
    mols O2 = grams/molar mass = ?

    Convert mols CH4 to mols CO2 using the coefficients in the balanced equation.
    Do the same with O2.
    It is likely that these two values for mols CO2 will not agree which means one of them is wrong. The correct value in limiting reagent problems is ALWAYS the smaller value and the reagent producing that value is the limiting reagent.

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  2. O2

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    2. 👎 0
  3. O2

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    2. 👎 0

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