Calculus

Solve dy/dx for sin(xy)=1+x^3-y^2

asked by C
  1. sin(xy)=1+x^3-y^2

    cos(xy) (y + xy') = 3x^2 - 2yy'
    y cos(xy) + xcos(xy) y' = 3x^2 - 2yy'
    (x cos(xy) + 2y) y' = 3x^2 - y cos(xy)

    y' = (3x^2 - y cos(xy)) / (x cos(xy) + 2y)

    posted by Steve

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