The initial temperature of a bomb calorimeter is 28.50°C. When a chemist carries out a reaction in this calorimeter, its temperature decreases to 27.45°C. If the calorimeter has a mass of 1.400 kg and a specific heat of 3.52 J/(g°C), how much heat is absorbed by the reaction?
yes
23.2
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1,470 J
To calculate the amount of heat absorbed by the reaction, we can use the equation:
q = m * c * ΔT
Where:
q = heat absorbed by the reaction
m = mass of the calorimeter
c = specific heat capacity of the calorimeter
ΔT = change in temperature
Let's plug in the values:
m = 1.400 kg
c = 3.52 J/(g°C) = 3520 J/(kg°C) (since 1 kg = 1000 g)
ΔT = 27.45°C - 28.50°C = -1.05°C (since the temperature decrease)
Now, let's substitute the values into the equation and calculate the heat absorbed by the reaction:
q = 1.400 kg * 3520 J/(kg°C) * (-1.05°C)
q = -5164.4 J
The negative sign indicates that heat is being released by the reaction. Therefore, the amount of heat absorbed by the reaction is 5164.4 J.