1) Calculate the tensile stress in a 33.000mm diameter rod subjected to a pull of 30.000kN.
ANS= MPa (Round to 3 decimal places)
Diameter = 33.000mm = 0.033m
30.000kN = 30000N
Area = pi*d^2/4
= 3.1416 * 0.033^2/ 4
= 3.1416 *0.001089/ 4
= 0.0034212024/ 4
= 8.553006*10^-4
= 0.0008553
Stress= Load/Area
= 30000/ 0.0008553
= 35075412.14Pa
= 35075.41214kPa
ANS = 35.07541214MPa
2) Consider that the rod was originally 1.000 meters long, and it was stretched 1.110mm by the pulling force. Calculate the strain produced in the rod.
ANS=(6decimal places)
1.110mm = 0.00111m
= 0.00111m/1m
ANS = 0.001110
Please check. Thank you.
To calculate the tensile stress in a rod subjected to a pull, you need to divide the force applied (in newtons) by the cross-sectional area of the rod (in square meters). Here's how you can calculate it:
1) Convert the diameter from millimeters to meters:
Diameter = 33.000mm = 0.033m
2) Convert the force from kilonewtons to newtons:
30.000kN = 30,000N
3) Calculate the cross-sectional area of the rod:
Area = π * (diameter/2)^2 / 4
= 3.1416 * (0.033/2)^2 / 4
= 3.1416 * 0.001089 / 4
= 0.0034212024 / 4
= 0.0008553 m^2
4) Calculate the stress:
Stress = Force / Area
= 30,000 / 0.0008553
= 35,075,412.14 Pa
≈ 35.075 MPa
Therefore, the tensile stress in the rod is approximately 35.075 MPa.
To calculate the strain produced in the rod, you need to divide the change in length of the rod by its original length. Here's how you can calculate it:
1) Convert the change in length from millimeters to meters:
1.110mm = 0.00111m
2) Calculate the strain:
Strain = Change in length / Original length
= 0.00111m / 1m
= 0.00111
Therefore, the strain produced in the rod is 0.00111 (to 6 decimal places).