# chemistry

What is the pH of a 1.24 mol/L solution of HCN(aq) if its Ka = 6.2 x 10-10

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posted by DrBob222
2. i know nothign abt it but can u help me through it.

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3. I'm sure you know something.
Write the equation.
HCN ==> H^+ + CN^-
Write the Ka expression.
Ka = (H^+)(CN^-)/(HCN) = 6.32 x 10^-10

Set up the ICE table and go from there.

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