A mechanic strikes a hammer with a velocity of 20 m/sec.the hammer stops in 0.02 seconds after striking the nail. Find the acceleration.
assuming constant acceleration, then since the velocity changed by -20m/s in .02 seconds,
a = v/t = -20m/s / .02s = -1000 m/s^2
Good
To find the acceleration, we can use the formula:
acceleration = (final velocity - initial velocity) / time
Here:
Initial velocity (u) = 20 m/sec
Final velocity (v) = 0 (since the hammer stops)
Time (t) = 0.02 seconds
Substituting these values into the formula, we get:
acceleration = (0 - 20) / 0.02
Simplifying the equation:
acceleration = -20 / 0.02
acceleration = -1000 m/sec²
Therefore, the acceleration of the hammer is -1000 m/sec². The negative sign indicates that the acceleration is in the opposite direction to the initial velocity.
To find the acceleration, we can use the formula:
acceleration (a) = (final velocity (v) - initial velocity (u)) / time (t)
In this case, the initial velocity (u) is the velocity with which the hammer strikes the nail, which is given as 20 m/s. The final velocity (v) is 0 m/s since the hammer stops. The time (t) is given as 0.02 seconds.
Substituting the values into the formula, we have:
a = (0 - 20) / 0.02
Simplifying further:
a = -20 / 0.02
a = -1000 m/s²
Therefore, the acceleration of the hammer is -1000 m/s². The negative sign indicates that the acceleration is in the opposite direction of the initial velocity (deceleration).