an electric oven of 2kW power heating is operated in a domestic circuit that has a current rating 5A. If the supply voltage is 220V. What result do you expect? Explain
P = V*I = 2000 W.
220I = 2000
I = 9.09 Amps.
The current too high for the circuit.
If the circuit is properly protected, the fuse will blow or the circuit breaker will trip.
To determine the result, we need to calculate the current drawn by the electric oven and compare it with the current rating of the domestic circuit.
The power of the electric oven is given as 2 kW, which is equivalent to 2000 watts. The formula for calculating power is:
Power (in watts) = Voltage (in volts) * Current (in amperes)
Rearranging the formula to calculate current:
Current (in amperes) = Power (in watts) / Voltage (in volts)
Plugging in the values for power (2000 watts) and voltage (220 volts):
Current (in amperes) = 2000 watts / 220 volts
Current = 9.09 amperes (approximately)
Since the calculated current (9.09A) is greater than the current rating of the domestic circuit (5A), we can expect that the circuit will be overloaded. This means that the domestic circuit is not capable of safely providing the required power for the electric oven. Using the oven in this configuration could potentially cause overheating and/or tripping the circuit breaker.
To resolve this, either the oven's power consumption needs to be reduced, or the circuit needs to be upgraded to handle higher currents. It is important to consult a qualified electrician to ensure the electrical system can handle the desired load safely.