Wha volum of steam is produced when log of propyrie is burnt in excess oxygen at s.t.p?
i guess log is 10g???...stp is standard temperature and pressure. in this condition, 1 mole of gas contains 22.4L.
Is it propyrie or propyne??? whateva it is, its an organic compound so would yield H2O and CO2 when combusted completely.
here's what you must do;
construct a balance equation for the complete combustion of propyrie.
obtain the mole ratio between propyrie and H2O.
calculate the mole of propyrie using m/Mr, and use the mole ratio to determine the mole of H2O steam.
use 1mole = 22.4L to determine the volume of H2O steam.
hope that helps...
Answer the question for me
Answers
To find the volume of steam produced when log of propylene is burnt in excess oxygen at standard temperature and pressure (STP), we need to balance the chemical equation for the combustion reaction of propylene.
The balanced chemical equation for the combustion of propylene (C3H6) can be written as follows:
C3H6 + O2 -> CO2 + H2O
From the equation, we can see that for every 1 mole of propylene burned, we get 1 mole of carbon dioxide (CO2) and 1 mole of water (H2O). Since we are interested in the volume of steam specifically, we focus on the number of moles of water produced.
At STP, 1 mole of any gas occupies 22.4 liters. Therefore, to calculate the volume of steam produced, we need to know the number of moles of water formed.
In this case, the volume of steam will be equal to the volume of water produced. To find the number of moles of water formed, we can use the stoichiometry of the balanced chemical equation.
By examining the equation, we can see that the stoichiometric ratio of C3H6 to H2O is 1:1. This means that for every 1 mole of propylene burned, 1 mole of water is produced.
Since the volume of steam is equal to the volume of water, if we burn 1 mole of propylene, we will produce 1 mole of steam, which is equal to 22.4 liters at STP.
Therefore, when 1 mole of propylene is burnt in excess oxygen at STP, the volume of steam produced is 22.4 liters.