Solve G(x) for the given domain.
G(x) = 3x 2 - 2x - 1
G(6) =
To find the value of G(x) when x = 6, we substitute x = 6 into the expression for G(x).
G(x) = 3x^2 - 2x - 1
G(6) = 3(6)^2 - 2(6) - 1
Now, we can simplify the expression.
G(6) = 3(36) - 12 - 1
G(6) = 108 - 12 - 1
G(6) = 96 - 1
G(6) = 95
Therefore, G(6) = 95.
To solve G(x) for the given domain, we substitute the value of x into the expression for G(x) and simplify.
Given: G(x) = 3x^2 - 2x - 1
To find G(6), substitute x = 6 into the expression for G(x):
G(6) = 3(6)^2 - 2(6) - 1
Now we simplify the expression:
G(6) = 3(36) - 2(6) - 1
= 108 - 12 - 1
= 95
Therefore, G(6) = 95.
eh? plug in 6 for x. What do you get?
If you're taking pre-cal, this should be a no-brainer.