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The problem I have to solve is log with base 2 ^6 multiply by log base 6 ^ 8.

I use the change of base formula and got log6/log2 * log8/log6

Which become
log6/log2 * log2()^3/ log 6

I'm stuck here thanks.

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  1. you are correct in that you wind up with

    log6/log2 * log8/log6

    Now, you almost had it, since you recognized (I think) that 8 = 2^3. So, you have

    = log8/log2
    = 3log2/log2
    = 3

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    Steve

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