Physics

Can anyone help with which formula I should use to solve this:
During a head on car crash, the car is designed to slow down as its front end crumples. If a person can survive an acceleration of -33 m/s how far must the front end crumple if the car was initially traveling at 28 m/s?

asked by Lynn
  1. v = vi - 33 t
    v = 0 at stop
    so
    0 = 28 - 33 t
    t = .848 seconds

    distance = vi t -(1/2)(33) t^2
    d = 28(.848) - 16.5 (.848)^2
    = 23.8 - 11.9
    = 11.9 meters (very long car)

    posted by Damon

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