I = E/R
A car has a 12 volt battery. The engine has a resistance of 0.22 ohms. How many amps will be drawn from the battery when the key is turned?
I (to the nearest hundredth) = amperes
To find the current (I) drawn from the battery when the key is turned, we can use Ohm's Law, which states that I = E/R, where I is the current, E is the voltage, and R is the resistance.
In this case, the voltage (E) is given as 12 volts, and the resistance (R) of the car engine is given as 0.22 ohms. Plugging in these values into the equation:
I = E/R
I = 12 volts / 0.22 ohms
I (to the nearest hundredth) = 54.55 amperes
Therefore, approximately 54.55 amperes will be drawn from the battery when the key is turned.