Physics

An infinite straight wire carrying a current I=5 A flowing to the right is placed above a rectangular loop of wire with width w=11 cm and length L=27 cm, as shown in the figure below. The distance from the infinite wire to the closest side of the rectangle is h=1.7 cm. The loop of wire has resistance R=0.31 Ohm.


(a) What is the magnitude (in Tesla) of the magnetic field due to the infinite wire at the point P in the rectangular loop, a distance r=3.2 cm from the wire (see figure).


In which direction does it point?


(b) Calculate the magnitude of the magnetic flux (in Tesla  m2) through the rectangular loop due to the magnetic field created by the infinite wire.

(c) Suppose the current in the infinite wire starts increasing in time according to I=bt, with b=50 Amps/sec. What is the magnitude (in Amps) of the induced current in the loop? Neglect any contribution to the magnetic flux through the loop due to the magnetic field created by the induced current.


(d) What is the direction of this current flow?

  1. 1
asked by Annoyingmous
  1. a) B = mu_0*I/(2*Pi*r)

    b) phi = (mu_0*I*L/(2*Pi))*ln(1+w/h)

    c) i = (-1/R)*(mu_0*L)/(2*Pi)*ln(1+w/h)*(di/dt)

    posted by ^_ ^
  2. What is di/dt ??

    posted by Phy
  3. Phy, it's the b in the variation I=bt. Just use the b value in the problem for (di/dt)

    posted by Anonymous
  4. Thanks, can u tell me the solutions of 1,4,6,9,10,11,12?

    posted by Phy
  5. the C is wrong for me using the b in di/dt

    posted by dd
  6. Have you guys gt 3,5,7,8,9,10,11,12...????? Let's help each other and get this done guys!!

    posted by robbo
  7. C is wrong ...

    posted by Sat
  8. Some people haven't done even one question.

    posted by boss
  9. I wonder if some people understand the subject at all. It is an insult to the lecturer.

    posted by boss
  10. Hey boss, how did u come across this topic if you have not googled the question? It's obvious that you cheat also!

    BTW - for C just use the value for b (the one in the question) b=(di/dt)

    posted by Sat
  11. Hey guys, what abput prob. 10?

    posted by Anonymous
  12. 10, b) how to solve

    posted by BG
  13. Please, problem 8!!!

    posted by Jack
  14. Problems 8-12 guys, please???/

    posted by robbo
  15. Please tell ans of any question please
    Q3 a=0 last part =0

    posted by P
  16. Anyone, can help with questions:

    11 c)
    10 b)
    8 d,e,f)
    5 b,d,e)

    posted by BG
  17. 11 a)
    q/(4*pi*E_0*(r^2)*k)

    11 b)
    q*k/(r^2)

    11 d) 0

    posted by BG
  18. anyone for question 7 please

    posted by me
  19. Hi BG, can you put the results for 8 a, b,c?

    posted by Jack
  20. Please, Q10?

    posted by AAA
  21. anyone for question 3 please??????

    posted by AAA
  22. 5 e)
    v= m*g*R/(B^2*W^2)

    posted by Jack
  23. 8 a)
    E = (st)/(S*E_0)
    S = Area

    8 b) E*d

    8 c)
    C = E*E_0*S/d

    posted by BG
  24. S = pi(b^2 - a^2)

    posted by BG
  25. Jack, did you solve anything else from this list:
    11 c)
    10 b)
    8 d,e,f)
    5 b,d)

    posted by BG
  26. me, I will exchange solution 8 on 7)

    posted by BG
  27. me, a = lambda/0.5
    d = lambda/0.125

    posted by BG
  28. denaminator may be different, it depends on drawing

    posted by BG
  29. How I can know my denominator watching my grahp BG?

    posted by AAA
  30. prob 8

    posted by BG
  31. I think drawings at all identical so don't worry

    posted by BG
  32. BG sorry don't have 8 yet, i'll post it as soon as i solve it and thanks for 7

    posted by me
  33. i have 5 do you still need 5b and 5d

    posted by me
  34. BG,

    8 d)

    B= mu_0*(r^2-a^2)*s/(2*r*pi*(b^2-a^2))

    posted by Jack
  35. BG, do you have 10 c and d?

    posted by Jack
  36. Please me, question 5

    posted by AAA
  37. 8 e)
    t*s^2/2*PI^2*(b^2-a^2)

    Please anyone 10 and 9c)

    posted by OVNI
  38. 5) a)=B(l-W)z(t)
    b)=(B*V*W)/R
    c)=(B^2*V*W^2)/R
    d)= (M*g*R)/(B^2*W^2)

    posted by me
  39. Please OVNI, 11 c)

    posted by Jack
  40. 8 f)
    Result of e multiplied by 2*pi*b*d

    posted by Jack
  41. i'm conufsed about the parentheses that might havve been omitted in OVNI's answer to 8e....

    t*s^2/(2*PI^2*(b^2-a^2) )


    Is this correct?

    posted by robbo
  42. I think a b is missing!

    t*s^2/(2*PI^2*b*(b^2-a^2) )

    posted by Jack
  43. Sorry, it's

    (t*s^2)/(2*PI^2*b*(b^2-a^2))

    Please, anyone 9c) and 10c)

    posted by OVNI
  44. 8f, 8e solutions aren't working out as given by OVNI and Jack... help guys?

    posted by robbo
  45. Please 11 c) and 10!

    posted by Jack
  46. Jack, 11c is 0.5*L*I^2

    posted by robbo
  47. Thank you so much!
    Question 10??

    posted by AAA
  48. Sorry, but I posted as I worked and I got a green check mark.
    Please any one 9 and 10

    posted by OVNI
  49. Sorry I meant 10c is 0.5*L*I^2.... the LC circuit sum, does anybody have 10 b and d??

    posted by robbo
  50. how do you get 11 b and c???

    posted by robbo
  51. Roboo, why in your 11c you use L, and I?????

    posted by OVNI
  52. I meant 10c OVNI! Mistake... SOrry!

    posted by robbo
  53. Please 10d) and 9c)

    posted by OVNI
  54. 9b????

    posted by robbo
  55. robbo, the same that 9 a)

    posted by Jack
  56. 9b = 9a, E1 = V/d1 and E2 = V/d2

    9c)try with charge conservation

    posted by 124
  57. robbo 10 b)

    posted by Jack
  58. 11 b)
    q*9*(10^9)/r^2
    r = distance from the origin

    posted by BG
  59. 10 b) 10 d) and 11 c) please!!!!

    posted by Jack
  60. 5A doesn't seem to work

    posted by w
  61. Please give ans for Q5 for values I am getting them last chance please

    What is the total magnetic flux through the loop (in Tesla m ) when is 62 cm. Include only the magnetic flux associated with the external field (i.e. ignore the flux associated with the magnetic self-field generated by the current in the wire loop). Note that you do not need to calculate or know at what time the loop is at this location.

    incorrect

    (b) Using Faraday's Law and Ohm's Law, find the magnitude (in Amps) of the induced current in the bar at the time when 1.00 m/sec. Note that you do not need to calculate or know at what time the loop has this speed.

    incorrect

    (c) Which way does the current flow around the loop, clockwise or counterclockwise?

    Status: correct

    (d) What is the total magnetic force (in Newtons) on the rigid wire loop when 1.00 m/sec? Again, ignore any effects due to the self magnetic field.


    direction:
    Status: correct


    magnitude (in Newtons):

    incorrect

    (e) What is the magnitude of the terminal speed (in m/sec) of the loop (i.e. the speed at which the loop will be moving when it no longer accelerates)?

    posted by P
  62. 8 e)

    poling vector = E*B/mu_0 = ??

    posted by BG
  63. it's correct ?

    posted by BG
  64. P, phi=B*w*(L-z)
    |em|=|dphi/dt|=B*w*V
    i=|em|/R=B*w*V/R
    F=watt/ms^-1=(|em|^2/R)*1/V

    posted by 124
  65. BG, OK

    posted by 124
  66. 10 b) please!

    posted by Jack
  67. 10b)= frequency that abs(i(t))=max

    posted by 124
  68. f= 1/(2*pi*sqrt(L*C))?

    posted by Jack
  69. and 10 d), please

    posted by Jack
  70. i(t)=I0*cos(w*t) and abs(i(t))=max if
    w*t=k*pi, for k=1=>t1=pi/w
    f=1/t1=w/pi=1/(pi*sqrt(L*C))

    posted by 124
  71. 124, i have E and B correct
    but

    pointing vector with formula E*B/mu_0, mu_0 = 4*pi*10^(-7), incorrect.

    pliz, tell where is error?

    posted by BG
  72. 10d)=>average p=v*i on [0,3*t1]

    posted by 124
  73. BG, S=E*B/mu_0
    = 1/(2*pi^2*b)*s^2*t/(b^2-a^2)

    posted by 124
  74. 10b) f=1/t1=w/pi=1/(pi*sqrt(L*C))

    posted by 124
  75. BG, B(r=b) = mu_0*s/(2*pi*b)is not the the previous B(r)

    posted by 124
  76. 124, thanks a lot, you the man. )

    posted by BG
  77. 124, 11 c) - Could you please help and give any hints on it?

    posted by BG
  78. 11 c) please!

    posted by Jack
  79. in 10d for P=V*I, where do we get V from???

    posted by robbo
  80. robbo, v=Ldi/dt
    P_mean=1/(3T-0)*int(v*i,0,3*T)
    T=2*pi*sqrt(L*C)

    11c)e)=>Q_net+ q = Q_encl in the gauss Law

    posted by 124
  81. S=E*B/mu_0
    = 1/(2*pi^2*b)*(s^2)*(t/(b^2-a^2))


    What's wrong with this formula guys??

    Please help?

    posted by robbo
  82. (t*s^2)/(2*(PI^2)*b*(b^2-a^2))

    posted by Jack
  83. robbo, formula is right, check s^2*t
    for example s=24u and t=5u
    s^2*t = 24*24*5*1u^3

    posted by 124
  84. 10 d) Positive or negative?

    posted by Jack
  85. Is this correct for 10 d)=

    P=1/3T * int(-L*w*(Imax)^2*sin(wt)*cos(wt), 0 , 3T)
    Thanks!!!

    posted by Jack
  86. Jack, and 124, for the formula:(t*s^2)/(2*(PI^2)*b*(b^2-a^2)) = 5.27300181668e-11


    at s=12uC/sec, t=1usec, b=0.0053m, a=0.0014m


    I've followed the formula, but the answer shows wrong... I hope you guys can help?

    posted by robbo
  87. Jack, the formula you've used is correct :)

    posted by robbo
  88. Q11 formulae, anybody??

    posted by robbo
  89. Jack, yes the formula is OK

    posted by 124
  90. 124, I have no idea what on earth I'm doing wrong, followed your formula... and input values and got the same answer everytime I tried, apparently its incorrect! :( Can you input my values and see what answer you get?

    posted by robbo
  91. robbo,sorry i forgot e_0
    (1u*12u^2)/(2*(PI^2)*5.3m*(5.3m^2-1.4m^2)*8.85e-12) =5.95215457341
    E =|E|er
    |E|=1/(4*pi*e_0*kappa)*q/r^2 for (a<r<b) |E|=1/(4*pi*e_0)*q/r^2 for r>=b

    posted by 124
  92. S=E*B/mu_0
    = 1/(2*pi^2*b*epsilon_0)*(s^2)*(t/(b^2-a^2))

    posted by 124
  93. guys, you can subscribe in the new course ReView (8.MReVx)

    posted by 124
  94. 10d)
    P=1/3T * int(-L*w*(Imax)^2*sin(wt)*cos(wt), 0 , 3T) = 0!!!!!

    T=2*pi*sqrt(L*C)

    posted by 124
  95. 124, i think its supposed to be t^2/(b^2-a^2) instead of t to the power of 1.

    posted by robbo
  96. 9c, 11c anybody?

    posted by robbo
  97. 11 c) Is the net charge positive or negative?

    posted by Jack
  98. THIS IS CHEATING!!! YOU ARE NOT FOLLOWING THE HONOUR CODE!!

    posted by MIT
  99. Dear MIT, you got here by???? Googling for what?

    posted by HarvardX
  100. 1c please

    posted by l
  101. 11 c) please!!!

    posted by Jack
  102. it seems that we cheated. So I leave. Good luck to all!

    posted by 124

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