Physics

If the critical angle for light at an interface between certain substances is 54.2 degrees, what is the polarizing angle at this same interface?

I am confused!

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asked by J
  1. Use the critical angle to get the index of refraction ratio, N1/N2

    Sin 54.2 = N2/N1 = 0.81106
    N1/N2 = 1.233

    For the polarizing (Brewster) angle, A

    tan A = N2/N1

    N2/N1 = 50.1 degrees

    See http://en.wikipedia.org/wiki/Brewster's_angle
    for detailed explanation

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    posted by drwls
  2. my book says the answer is 39 degrees..

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    posted by J
  3. Right.
    arctan N2/N1 = arctan 0.81106 = 39.0 degrees

    I failed to use the formula correctly

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    posted by drwls

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