Four resistors 2.1Ω, 3.2 Ω, 4.3 Ω, and 5.4 Ω are connected in a series to a 9 V battery. The effective resistance in the circuit is:
The sum of the individual resistances: 15.0 ohms.
You do not need the battery voltage for that question.
To find the effective resistance in a series circuit, you simply add up the resistances of each individual resistor.
In this case, you have four resistors with values of 2.1 Ω, 3.2 Ω, 4.3 Ω, and 5.4 Ω. To find the total effective resistance, you add these values together:
2.1 Ω + 3.2 Ω + 4.3 Ω + 5.4 Ω = 14 Ω
Therefore, the effective resistance in the circuit is 14 Ω.