Your English teacher has decided to randomly assign poems for the class to read. The syllabus includes 4 poems by Shakespeare, 5 poems by Coleridge, 2 poems by Tennyson, and 2 poems by Lord Byron. What is the probability that you will be assigned a poem by Coleridge and then a poem by Lord Byron?
Possible answers:
7/13, 9/13, 5/78, 6/13
To calculate the probability of being assigned a poem by Coleridge and then a poem by Lord Byron, we need to consider the total number of possible outcomes and the number of favorable outcomes.
The total number of possible outcomes is the total number of poems, which is the sum of the poems by Shakespeare, Coleridge, Tennyson, and Lord Byron.
Total number of poems = 4 + 5 + 2 + 2 = 13
The number of favorable outcomes is the product of the number of poems by Coleridge and the number of poems by Lord Byron.
Number of poems by Coleridge = 5
Number of poems by Lord Byron = 2
Therefore, the number of favorable outcomes is given by:
Number of favorable outcomes = Number of poems by Coleridge * Number of poems by Lord Byron = 5 * 2 = 10
The probability is then calculated by dividing the number of favorable outcomes by the total number of possible outcomes:
Probability = Number of favorable outcomes / Total number of possible outcomes = 10 / 13 ≈ 0.769
So, the probability is approximately 0.769, which can be simplified as 10/13. Therefore, the answer is 10/13.
To find the probability of being assigned a poem by Coleridge and then a poem by Lord Byron, we need to consider the total number of possible outcomes and the number of favorable outcomes.
First, let's calculate the total number of possible outcomes. Since there are 4 poems by Shakespeare, 5 poems by Coleridge, 2 poems by Tennyson, and 2 poems by Lord Byron, the total number of poems is 4 + 5 + 2 + 2 = 13.
Next, let's calculate the number of favorable outcomes. We want to be assigned a poem by Coleridge first and then a poem by Lord Byron. There are 5 poems by Coleridge and 2 poems by Lord Byron, so the number of favorable outcomes is 5 * 2 = 10.
Now, we can calculate the probability by dividing the number of favorable outcomes by the total number of possible outcomes:
Probability = Number of Favorable Outcomes / Total Number of Possible Outcomes
Probability = 10 / 13
Therefore, the probability of being assigned a poem by Coleridge and then a poem by Lord Byron is 10/13.
No replacement (otherwise two identical poems)
Total=4+5+2+2=13 poems
5 Colerdge, 2 Byron
So
P(CB)=(5/13)*(2/12)