How much hydrogen gas (mL) would be rpoduced at 25 degreez C and 1.34 atm if 5.5 grams of zinc reacts with 25mL of 0.05 M hydgrchloric acid? Please respond with how u found the answer
Zn+2HCl -> ZnCl2 + H2
5.5 g of Zn
= 5.5/65.382 M
=0.0841 M
25 ml of 0.05M HCl
= 25/1000*0.05 M
= 0.00125 M < 0.0841/2
So the quantity of HCl governs.
Assuming all HCl is consumed,
amount of Hydrogen
= 0.00125/2 M
= 0.000625 M
Convert that to the required temperature and pressure.