(2 − (2.479/35))^7t= 29

1. take log of both sides

log [(2 − (2.479/35))^7t= 29] = log 29
7t log(2 − (2.479/35)) = log 29
7t(.2853...) = log 29
7t = log 29/.2853... = 5.1245...
t = .732078
= appr .73

check:
using 2 decimals

(2 − (2.479/35))^7t= 29.00000003 , not bad

posted by Reiny

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