math calculus (please help me)

Solve for t. (Round your answer to two decimal places.


(2 − (2.479/35))^7t= 29

asked by steven
  1. take log of both sides

    log [(2 − (2.479/35))^7t= 29] = log 29
    7t log(2 − (2.479/35)) = log 29
    7t(.2853...) = log 29
    7t = log 29/.2853... = 5.1245...
    t = .732078
    = appr .73

    check:
    using 2 decimals

    (2 − (2.479/35))^7t= 29.00000003 , not bad

    posted by Reiny

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