if 15.0g Si and 30.0g Chlorine gas are reacted together, what vol. of SiCl4 will be produced assuming a 75% yield? Density of SiCl4 =1.483g/ml.
Si + 2l2 ==> SiCl4
mols Si = grams/atomic mass = ?
mols Cl2 = grams/molar mass.
Convert mols Si to mols SiCl4 using the coefficients in the balanced equation.
Convert mols Cl2 to mols SiCl4 the same way.
It is likely these two numbers will not be the same which means one of them is not right; the correct value in limiting reagent problems is ALWAYS the smaller value and the reagent producing that value is the limiting reagent.
Using the smaller value for mols SiCl4, convert to grams. g = mols x molar mass.
That is the theoretical yield.
Actual yield = theor yield x 0.75 = ?
Then use mass = volume x density to convert to volume.
To find the volume of SiCl4 produced, we need to follow these steps:
Step 1: Calculate the number of moles of Si and Cl2 involved in the reaction.
We have the masses of Si (15.0 g) and Cl2 (30.0 g), so we need to convert these masses into moles. To do this, we'll divide the masses by their respective molar masses.
The molar mass of Si (silicon) is 28.086 g/mol, so the number of moles of Si is:
moles of Si = mass of Si / molar mass of Si
moles of Si = 15.0 g / 28.086 g/mol
The molar mass of Cl2 (chlorine gas) is 70.906 g/mol, so the number of moles of Cl2 is:
moles of Cl2 = mass of Cl2 / molar mass of Cl2
moles of Cl2 = 30.0 g / 70.906 g/mol
Step 2: Determine the limiting reactant.
To find the limiting reactant, we have to calculate the mole ratios between Si and Cl2. The balanced chemical equation for the reaction will help us with this. However, since one is not provided, we'll assume a balanced equation based on the information given: Si + 2Cl2 → SiCl4.
From the balanced equation, we can see that the mole ratio between Si and Cl2 is 1:2. Therefore, the limiting reactant is the reactant that produces fewer moles of product or the reactant that is consumed completely.
Step 3: Determine the moles of SiCl4 produced.
Since the mole ratio between Si and SiCl4 is 1:1 (from the balanced equation), the moles of SiCl4 produced are equal to the moles of Si.
Step 4: Calculate the mass of SiCl4 produced.
mass of SiCl4 = moles of SiCl4 × molar mass of SiCl4
mass of SiCl4 = moles of Si × molar mass of SiCl4
Step 5: Calculate the volume of SiCl4 produced.
To calculate the volume of SiCl4 produced, we'll use the density of SiCl4 and the mass we calculated in Step 4.
volume of SiCl4 = mass of SiCl4 / density of SiCl4
Given the density of SiCl4 is 1.483 g/mL, we divide the mass of SiCl4 by the density to get the volume.
volume of SiCl4 = (mass of Si × molar mass of SiCl4) / density of SiCl4
Finally, to account for the 75% yield, we multiply the calculated volume by 0.75.
volume of SiCl4 (with 75% yield) = (mass of Si × molar mass of SiCl4) / density of SiCl4 × 0.75
Now, you can substitute the values into the equation to calculate the volume of SiCl4 produced.