A group of 30 people consists of 15 children, 10 men, and 5 women. Tom and Jerry are two of the men in the group. Five people are picked at random without replacement.

2A - Find the chance the first person picked is a man, given that the fourth and fifth people picked are children.

2B - Find the chance that more than two women are picked.

2C - Find the chance that Tom and Jerry both get picked.

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cheating for final exam stat 2.2x eh? :D i want the answer too!!! :P

2b : .40189

A. If it is the first pick, it doesn't matter what the subsequent picks are, 10/30.

B. More than two women means 3, 4 or 5 women.

If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events.

For 5 women, P = 5/30 * 4/29 * 3/28 * 2/27 * 1/26 = ?

For 4 women, P = 5/30 * 4/29 * 3/28 * 2/27 * 25/26 = ?

For 3 women, P = ?

Either-or probabilities are found by adding the individual probabilities.

C. P = 1/30 * 1/29 = ?

2B is 0.40189 is wrong

2C is also wrong.

2a is 10/28

2B : Hypergyometric: N=30, G=5, n=5, g>=3

Value: 2.193%

2C : Again Hypergeometry

2 Good items (Tom & Jerry).

So in 2C, N=30, G=2, n=5, g=2
Probability = 0.0299 = 0.023

2b .3571

2c ?

sorry 2a .3571

2b .0229 ?

is that 2C = 0.0229885?

LOL. Yes. You guys really know your probability. And what are you going to do with your certificate? Use it as toilet paper? Well that's about all it's good for. You've made sure of that.