what is the normality and nature of the mixture obtained by mixing 0.62 gram of na2co3.h2o to 100 ml of 0.1N h2so4

To determine the normality and nature of the mixture obtained by mixing Na2CO3.H2O and H2SO4, we need to first calculate the number of moles of each compound.

Step 1: Calculate the number of moles of Na2CO3.H2O (sodium carbonate):

To calculate the number of moles, we need to divide the mass of Na2CO3.H2O by its molar mass. The molar mass of Na2CO3.H2O is the sum of the atomic masses of its constituent elements.

The molar mass of Na = 22.99 g/mol
The molar mass of C = 12.01 g/mol
The molar mass of O = 16.00 g/mol
The molar mass of H = 1.01 g/mol

Na2CO3.H2O = (2 * 22.99 g/mol) + 12.01 g/mol + (3 * 16.00 g/mol) + (2 * 1.01 g/mol) = 105.99 g/mol

Now, we can calculate the number of moles of Na2CO3.H2O:

Number of moles = mass / molar mass = 0.62 g / 105.99 g/mol

Step 2: Calculate the number of moles of H2SO4 (sulfuric acid):

The given concentration of H2SO4 is 0.1 N (Normality), which means it is given in terms of equivalent moles.

To convert Normality to molarity (mol/L), we need to know the equivalence factor, which represents the number of equivalents of the solute per mole of the solute.

For H2SO4, the equivalence factor is 2 because each mole of H2SO4 can donate two moles of H+ ions.

So, the molarity (M) is calculated using the equation:

Molarity (M) = Normality (N) × equivalence factor

M = 0.1 N × 2 = 0.2 M

Now, we can calculate the number of moles of H2SO4:

Number of moles = volume (L) × molarity (M) = 0.1 L × 0.2 M

Step 3: Determine the normality of the mixture:

The normality of the mixture is the sum of the normalities of the individual components. In this case, we have Na2CO3.H2O and H2SO4, so:

Normality of the mixture = Normality of Na2CO3.H2O + Normality of H2SO4

Step 4: Determine the nature of the mixture:

The nature of the mixture can be determined based on the stoichiometry of the reaction between Na2CO3.H2O and H2SO4. The balanced chemical equation for the reaction is:

Na2CO3 + H2SO4 -> Na2SO4 + H2O + CO2

From the balanced equation, we can see that 1 mole of Na2CO3 reacts with 1 mole of H2SO4 to produce 1 mole of Na2SO4, 1 mole of H2O, and 1 mole of CO2. The nature of the mixture will depend on the limiting reactant.

To determine the limiting reactant, we compare the moles of each reactant calculated in Step 1 and Step 2. The reactant with fewer moles will be the limiting reactant.

Once we determine the limiting reactant, we can calculate the moles of the products formed and use the stoichiometry to determine the normality and nature of the mixture.

By following these steps, you can determine the normality and nature of the mixture obtained by mixing Na2CO3.H2O and H2SO4.