2x-3y=4
y=-x-3
i know x=4/12=1/3
just plug in 1/3 for x into either of the two equations.
y=-x-3
y = -1/3 + 1/3 - 3
y = -3
actually, x is not 1/3
y = -x-3 so
2x-3(-x-3) = 4
2x+3x+9 = 4
5x = -5
x = -1
so, y=-(-1)-3 = -2
To find the value of x in the given system of equations, we can use the method of substitution. Let's solve the second equation for y and substitute it into the first equation.
Given equations:
1) 2x - 3y = 4
2) y = -x - 3
Substitute equation 2) into equation 1):
2x - 3(-x - 3) = 4
Distribute the -3:
2x + 3x + 9 = 4
Combine like terms:
5x + 9 = 4
Isolate the x term by subtracting 9 from both sides:
5x = 4 - 9
5x = -5
Divide both sides by 5 to solve for x:
x = -5/5
x = -1
Therefore, the value of x is -1 in the given system of equations.