Physical Science

Blood is pumped from the heart at a rate of 5L/min into the aorta of radius 2.0cm. Assuming that the density of blood 1x103 kg/m3 .Determine the velocity of blood through
the aorta

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asked by Janaiby
  1. Q=vA
    Q=5L/min=8.3e-5 m^3/sec
    A= pi*r^2=3.14*4*10^-4=0.001256 m2
    v=8.3e-5/0.001256 = 0.006m/sec = 0.6cm/sec

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    posted by najat
  2. for rate 4.5 L/min and radius r = 1.1 cm

    rate of blood pumped from the heart is = 4.5 L/min

    we know that 1 L = 1000 cm^3

    the flow rate in cm^3/s , by heart is = 4.5*1000/60 cm^3/s = 75 cm^3/!@#$%^&he area of aorta is A = pi*r^2 = pi*1.1^2 = 3.80132 cm^2

    now the rate of flow is A*v ----------(A)

    where A is area of aorta and v is speed of blood in aorta

    equating (H) to (A) ( from equation of continuity A1*V1 = A2*V2)

    75 = A*v

    v = 75/A

    v = 75/3.80132 cm/s

    v = 19.7299885303 cm/s

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    posted by nnn

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