Physics

An object of mass 3.5x1023kg circles the earth and is attracted to it with a force whose magnitude is given be GMeM/r^2. If the period of rotation is 22 days, what is the distance from the earth to the object? Here G=6.67x10-11 Nm2/kg2, Me=6x1024 kg.

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asked by Charlie
  1. G Me M/r^2 = M V^2/r

    Express V in terms of the period P = 22 days = 1.90*10^6 seconds

    2 pi r/P = V

    G Me/r^2 = 4 pi^2 r/P^2

    4 pi^2/(G*Me) = r^3/P^2

    Solve for r.

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    posted by drwls

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