cd2+ (aq) +ni(s)---> cd(s) + ni2+ (aq) what is the half reaction
To determine the half-reaction in the given chemical equation, we need to separate the oxidation half-reaction and the reduction half-reaction.
Step 1: Identify the atoms that undergo changes in oxidation states. In this equation, the atoms undergoing oxidation state changes are Cd and Ni.
Step 2: Determine the initial and final oxidation states of the atoms.
- For Cd: Cd changes from +2 in Cd2+ (aq) to 0 in Cd(s).
- For Ni: Ni changes from 0 in Ni(s) to +2 in Ni2+ (aq).
Step 3: Write the half-reaction for oxidation and reduction.
Oxidation half-reaction: Cd2+ (aq) → Cd(s)
Reduction half-reaction: Ni(s) → Ni2+ (aq)
The oxidation half-reaction shows the species being oxidized, which is Cd2+ (aq), and how it decreases its oxidation state by gaining electrons and forming Cd(s).
The reduction half-reaction shows the species being reduced, which is Ni(s), and how it increases its oxidation state by losing electrons and forming Ni2+ (aq).
Therefore, the half-reactions for the given chemical equation are:
Oxidation half-reaction: Cd2+ (aq) → Cd(s)
Reduction half-reaction: Ni(s) → Ni2+ (aq)